Albert G wrote
However one of the hands-on in the lecture on slide 12 is to implement "arr[7] = 0". That is not really possible since I have no way to specify where "arr" is going to be stored in memory - or rather I have no way to tell the assembler that "arr" occupies, say, 32 words of ram.
Assume that
arr is an address in RAM, but don't worry about there being no way to allocate a block of storage. Your Hack code will need to set the 7th byte after
arr to 0.
(When you get to chapter 7 you'll see that blocks of storage are dynamically allocated and always referenced via pointers.)
--Mark