confusion in CPU emu

[liangke]

my code is:
D=D-A
@JUMP1
D;JEQ
@0
D=A
@JUMP2
0;JMP
(JUMP1)
@-1
D=A
(JUMP2)
@17
D=A
In CPU emu the code is :
30 D=D-A
31 @115
32 D;JEQ
33 @0
34 D=A
35 @386
36 0;JMP
37
38 D=A
39 @17

the line of 37 is 0
when the emu execute the line 37 ,the PC is to set 0.the code was reseted.
why CPU emu  has  assemble this code to this form.
and why execute line 37 ,the PC was set 0.
Thank you!

[liangke]

I think the code
@-1
it in mem should be :
0111 1111 1111 1111
not
1111 1111 1111 1111

how can I figure it?

[cadet1620]

@-1 is an illegal command.

The argument to @ commands must be a number between 0 and 32767, inclusive.  You can set the A register to -1 by using the A=-1 command.

If you want to set any other negative number into A you need to do something like
    @27
    A=-A
or to get -27 into D
    @27
    D=-A

--Mark